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PU-202 / L03 · lecture

Building the Time-Dependent Schrödinger Equation

~6 min read · Tier toggle changes depth (T1 plain · T2 standard · T3 rigour)

BEFORE YOU START

You should be comfortable with the statistical interpretation of the wavefunction, specifically that \( |\Psi(\mathbf{r}, t)|^2 \) represents probability density, and familiar with the de Broglie relation \( p = \hbar k \) and the Planck–Einstein relation \( E = \hbar \omega \).

Why this matters

The Schrödinger equation is the fundamental dynamical law of non-relativistic quantum mechanics, replacing Newton's second law.

In classical mechanics, we predict the future position of a particle by solving \( F = ma \). In quantum mechanics, we cannot track a precise trajectory. Instead, we track the evolution of the wavefunction \( \Psi(\mathbf{r}, t) \). The Time-Dependent Schrödinger Equation (TDSE) tells us exactly how this wavefunction changes with time under the influence of a potential. It is the engine that drives all quantum dynamics, from atomic transitions to electron tunnelling.

The Core Idea: A First-Order Wave Equation

Imagine you have a snapshot of a quantum state at time \( t = 0 \). To find the state at \( t = 1 \) second, you need a rule. The TDSE provides this rule. Unlike the classical wave equation, which is second-order in time (like a vibrating string), the Schrödinger equation is first-order in time. This means that if you know the wavefunction at one instant, you can uniquely determine its future evolution. The equation links the time evolution of the wavefunction to its spatial curvature. Roughly speaking, the "bumpiness" of the wave in space determines how fast the phase of the wave rotates in time. This connection between spatial shape and temporal evolution is the heart of quantum dynamics.

From Dispersion to Differential Equation

We can derive the form of the TDSE by demanding that it reproduce the known energy-momentum relationship for a free particle. For a free particle, \( V = 0 \), and the total energy is purely kinetic: \( E = \frac{p^2}{2m} \). Using the quantum relations \( E = \hbar \omega \) and \( p = \hbar k \), we get the dispersion relation:

\[ \hbar \omega = \frac{\hbar^2 k^2}{2m} \]

We seek a wave equation whose plane wave solutions \( \Psi \propto e^{i(\mathbf{k}\cdot\mathbf{r} - \omega t)} \) satisfy this relation. The time derivative \( \partial_t \) acts on the exponential to give \( -i\omega \), and the spatial Laplacian \( \nabla^2 \) acts to give \( -k^2 \). To match the dispersion relation, we need an operator equation where \( i\hbar \partial_t \) corresponds to \( E \) and \( -\frac{\hbar^2}{2m}\nabla^2 \) corresponds to \( \frac{p^2}{2m} \). This leads directly to the free-particle TDSE:

\[ i\hbar \frac{\partial \Psi}{\partial t} = -\frac{\hbar^2}{2m} \nabla^2 \Psi \]

When a potential \( V(\mathbf{r}, t) \) is present, the total energy is \( E = \frac{p^2}{2m} + V \). We simply add the potential term to the right-hand side, multiplying the wavefunction by \( V \). This yields the general TDSE for a single particle in a real scalar potential.

The Hamiltonian Operator

The TDSE can be written compactly using the Hamiltonian operator \( \hat{H} \). The Hamiltonian represents the total energy of the system. In position space, it is defined as:

\[ \hat{H} = -\frac{\hbar^2}{2m} \nabla^2 + V(\mathbf{r}, t) \]

The TDSE then takes the elegant form:

\[ i\hbar \frac{\partial \Psi}{\partial t} = \hat{H} \Psi \]

This form highlights a crucial structural feature: the equation is linear in \( \Psi \). If \( \Psi_1 \) and \( \Psi_2 \) are solutions, then any linear combination \( c_1 \Psi_1 + c_2 \Psi_2 \) is also a solution. This linearity is the mathematical basis for the superposition principle, which allows quantum systems to exist in multiple states simultaneously. The Hamiltonian is a Hermitian operator, ensuring that its eigenvalues (the allowed energy levels) are real numbers, which is physically necessary for energy measurements.

Time Evolution and Phase

Consider a stationary state, where the potential is time-independent and the wavefunction is an energy eigenstate: \( \Psi(\mathbf{r}, t) = \psi(\mathbf{r}) e^{-iEt/\hbar} \). Substituting this into the TDSE, the time derivative yields \( -iE \), and the spatial part yields \( E \psi(\mathbf{r}) \). The equation reduces to the Time-Independent Schrödinger Equation (TISE):

\[ \hat{H} \psi(\mathbf{r}) = E \psi(\mathbf{r}) \]

The time dependence is entirely contained in the phase factor \( e^{-iEt/\hbar} \). This phase rotates with angular frequency \( \omega = E/\hbar \). While the probability density \( |\Psi|^2 = |\psi|^2 \) remains constant in time for such states, the phase is physically significant. It determines interference effects when different energy states are superposed. The TDSE thus governs not just the magnitude of the wave, but its phase evolution, which is critical for phenomena like quantum beats and tunnelling.

The derivation

◆ DERIVATION EMBED · D-137 · not re-derived here

The Time-Dependent Schrödinger Equation

For a single non-relativistic particle of mass m moving in a real scalar potential V(r,t), the complex wavefunction Ψ(r,t) obeys the linear first-order-in-time equation iℏ ∂tΨ = −(ℏ²/2m)∇²Ψ + VΨ. This is the unique wave equation that (i) is linear in Ψ, (ii) is first order in time, and (iii) forces every free plane wave Ψ ∝ ei(k·r−ωt) to satisfy the non-relativistic dispersion ℏω = ℏ²k²/2m built from the de Broglie relation p = ℏk and the Planck–Einstein relation E = ℏω.

iℏ ∂Ψ/∂t = −(ℏ²/2m) ∇²Ψ + V(r,t)Ψ = ĤΨ
Open full derivation →
Tier 3 · watch out

A common misconception is that the wavefunction \( \Psi \) itself is a physical field like the electromagnetic field. In standard non-relativistic QM, \( \Psi \) is a probability amplitude. Only \( |\Psi|^2 \) is directly observable. However, the phase of \( \Psi \) is physically real; changing the phase globally does not change \( |\Psi|^2 \), but changing the phase locally (e.g., via a magnetic vector potential) does affect interference patterns. The TDSE preserves the norm \( \int |\Psi|^2 d^3r = 1 \) over time, ensuring probability is conserved, but the phase is not static: each energy component advances at its own rate \( E/\hbar \), and it is these relative phases that make a superposition change in time. C

Worked example

Problem. A free electron (mass \( m = 9.11 \times 10^{-31} \ \mathrm{kg} \)) is in a state described by the wavefunction \( \Psi(x, t) = A e^{i(kx - \omega t)} \). Given that the wave number is \( k = 2.0 \times 10^{10} \ \mathrm{m^{-1}} \), calculate the angular frequency \( \omega \) of this state. Use \( \hbar = 1.055 \times 10^{-34} \ \mathrm{J \cdot s} \).

  1. Identify the dispersion relation for a free particle: \( \hbar \omega = \frac{\hbar^2 k^2}{2m} \).
  2. Rearrange to solve for \( \omega \): \( \omega = \frac{\hbar k^2}{2m} \).
  3. Substitute the given values: \( k = 2.0 \times 10^{10} \ \mathrm{m^{-1}} \), \( m = 9.11 \times 10^{-31} \ \mathrm{kg} \), \( \hbar = 1.055 \times 10^{-34} \ \mathrm{J \cdot s} \).
  4. Calculate \( k^2 \): \( (2.0 \times 10^{10})^2 = 4.0 \times 10^{20} \ \mathrm{m^{-2}} \).
  5. Calculate the numerator: \( \hbar k^2 = (1.055 \times 10^{-34}) \times (4.0 \times 10^{20}) = 4.22 \times 10^{-14} \ \mathrm{J \cdot m^{-2} \cdot s} \).
  6. Calculate the denominator: \( 2m = 2 \times 9.11 \times 10^{-31} = 1.822 \times 10^{-30} \ \mathrm{kg} \).
  7. Divide to find \( \omega \): \( \omega = \frac{4.22 \times 10^{-14}}{1.822 \times 10^{-30}} \approx 2.32 \times 10^{16} \ \mathrm{rad/s} \).
\[ \omega \approx 2.32 \times 10^{16} \ \mathrm{rad/s} \]

Units check. \( \frac{\mathrm{J \cdot s \cdot m^{-2}}}{\mathrm{kg}} = \frac{\mathrm{kg \cdot m^2/s^2 \cdot s \cdot m^{-2}}}{\mathrm{kg}} = \frac{\mathrm{kg \cdot m^2/s}}{\mathrm{kg \cdot m^2}} \cdot \mathrm{s} = \frac{1}{\mathrm{s}} \). Since angular frequency is in radians per second, and radians are dimensionless, the units are consistent.

CHECK YOURSELF

Three quick tests

  1. Is the TDSE first-order or second-order in time?
    AnswerFirst-order. This ensures unique evolution from an initial state.
  2. What is the physical meaning of the Hamiltonian operator \( \hat{H} \)?
    AnswerIt represents the total energy (kinetic plus potential) of the system.
  3. If \( V(\mathbf{r}, t) = 0 \), what is the relationship between \( \omega \) and \( k \)?
    Answer\( \omega = \frac{\hbar k^2}{2m} \). This is the non-relativistic dispersion relation.
PROBLEMS

Problem set for PU-202 →

Each derivation in this unit ends with five graded problems with full solutions.

NOTES

Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.

Derivations cited: D-137 · Threads: matter, waves, energy