The Feynman Propagator
Statement
For a free real scalar field \(\phi(x)\) of mass \(m\) satisfying the Klein–Gordon equation, the time-ordered vacuum two-point function \(D_F(x-y)\equiv\langle 0|T\,\phi(x)\phi(y)|0\rangle\) is a Green's function of the Klein–Gordon operator, \((\Box_x+m^2)\,D_F(x-y)=-\,i\,\delta^{(4)}(x-y)\), whose momentum-space representation \(\displaystyle D_F(x-y)=\int\!\frac{d^4p}{(2\pi)^4}\,\frac{i}{p^2-m^2+i\epsilon}\,e^{-ip\cdot(x-y)}\) is fixed uniquely by the \(+i\epsilon\) contour prescription, which encodes the time ordering.
Why it matters
The Feynman propagator is the single most-used object in perturbative quantum field theory: it is the amplitude for a particle to propagate between two spacetime points, the internal line of every Feynman diagram, and the building block from which all scattering amplitudes are assembled through Wick's theorem. Every tree-level cross section and every loop integral is written in terms of \(D_F\).
Its defining feature is not that it solves the Klein–Gordon equation — many Green's functions do — but which one it is. The retarded, advanced, and Feynman propagators share the same differential equation and differ only in how their poles are circumvented. The \(+i\epsilon\) prescription is the physics: it propagates positive-frequency (particle) modes forward in time and negative-frequency (antiparticle) modes backward, exactly reproducing the time-ordering \(T\). This is where causality and the particle/antiparticle structure of the vacuum enter the formalism.
Assumptions
Derivation
Result
Reading. The time-ordered vacuum expectation value \(\langle 0|T\phi(x)\phi(y)|0\rangle\) inverts the Klein–Gordon operator with a unit imaginary source at coincident points. Among all Green's functions of \((\Box+m^2)\), the \(+i\epsilon\) prescription selects the one that propagates positive-frequency modes forward in time and negative-frequency modes backward — the amplitude for the vacuum to create a quantum at the earlier point and absorb it at the later point (or the antiparticle in reverse). It is the internal line of every Feynman diagram.
Units check. In natural units a scalar field in four dimensions has mass dimension \([\phi]=1\), so \([D_F]=[\phi]^2=2\). In the momentum integral \([d^4p]=4\) and \([\,i/(p^2-m^2)\,]=-2\), giving \(4-2=2\). ✓ In the differential form \([\Box+m^2]=2\) and \([\delta^{(4)}(x-y)]=4\) (since \([d^4x]=-4\)), so \([(\Box+m^2)D_F]=2+2=4=[\delta^{(4)}]\). ✓
Limiting cases
- Massless limit \(m\to 0\): \(\tilde D_F(p)=i/(p^2+i\epsilon)\); in position space \(D_F(x)=\dfrac{-1}{4\pi^2}\dfrac{1}{x^2-i\epsilon}\), the photon-like \(1/x^2\) propagator.
- Static / equal-time limit: the spatial Fourier transform \(\int\!\frac{d^3p}{(2\pi)^3}\frac{e^{i\vec p\cdot\vec r}}{\vec p^2+m^2}=\dfrac{e^{-mr}}{4\pi r}\) is the Yukawa potential; the mass sets the range \(1/m\).
- Heavy-mass / large \(m\): \(\tilde D_F\to -i/m^2\), a contact interaction; the particle cannot propagate and the exchange collapses to a point (basis of effective field theory).
- Large spacelike separation \(r=\sqrt{-x^2}\gg 1/m\): \(D_F\sim e^{-mr}\), exponential decay — no signal, only virtual leakage over a Compton wavelength.
- On the mass shell \(p^2\to m^2\): the propagator diverges as \(i/(p^2-m^2+i\epsilon)\); the imaginary part \(\to \pi\,\delta(p^2-m^2)\) is the physical single-particle pole.
Breaks when
- Interactions are turned on. The free-field equation of motion (step 8) fails; \((\Box+m^2)\phi=-\lambda\phi^3/6\) etc. The two-point function becomes the full propagator \(\tilde D(p)=i/[p^2-m^2-\Sigma(p^2)+i\epsilon]\) with a self-energy \(\Sigma\) that shifts the pole (mass renormalization), adds a finite residue \(Z<1\), and grows a branch cut above the multiparticle threshold. \(D_F\) is then not a Green's function of the free operator.
- The state is not the vacuum. At temperature \(T\) or finite density the ensemble average replaces \(\langle 0|\cdots|0\rangle\); \(\langle a^\dagger a\rangle=n_B(E_{\vec p})\ne 0\) adds \(2\pi\,\delta(p^2-m^2)\,n_B(|p^0|)\) to the propagator. Real-time thermal field theory requires the full \(2\times 2\) Schwinger–Keldysh matrix, not a single \(D_F\).
- The contour is chosen differently. Replacing \(+i\epsilon\) by the retarded prescription \(p^0\to p^0+i\epsilon\) (both poles below the axis) gives the same differential equation but a propagator supported only in the forward light cone — a classical, not time-ordered, object. The Green's-function statement survives; the identification with \(\langle 0|T\phi\phi|0\rangle\) does not.
- Spacetime is curved or a boundary is present. Translation invariance is lost, \(D_F(x-y)\) is no longer a function of \(x-y\) alone, the mode expansion of step 2 has no global positive-frequency split, and the very notion of "the vacuum" becomes observer-dependent (Unruh/Hawking).
Failure modes
- Sign of the source. Writing \((\Box+m^2)D_F=+i\delta^{(4)}\) or \(=\delta^{(4)}\). The overall factor of \(i\) and its sign are fixed by the mode normalization and the equal-time commutator; getting them wrong flips every amplitude's phase.
- Wrong pole for the wrong metric. Using \(i/(p^2-m^2+i\epsilon)\) with signature \((-,+,+,+)\). In that convention \(p^2=-{p^0}^2+\vec p^2\) and the correct Feynman denominator is \(-i/(p^2+m^2-i\epsilon)\); mixing conventions inverts the contour.
- Dropping the \(i\epsilon\) as "a technicality." Without it the \(p^0\) integral is undefined; the \(i\epsilon\) is the entire content that distinguishes \(D_F\) from the retarded, advanced, or Wightman functions, all of which solve the same equation.
- Forgetting that \(p^0\) is off shell. Treating the internal-line four-momentum as satisfying \(p^0=E_{\vec p}\). In the full four-dimensional integral \(p^2\ne m^2\) in general — that is what "virtual" means; only the poles are on shell.
- Missing the second delta-term. When differentiating \(T\)-products, students often keep only the \(\delta(x^0-y^0)\) from one \(\theta\) and forget the second, losing the factor that combines into the commutator (steps 3, 5).
Discussion
The derivation exposes a clean division of labor. The Klein–Gordon operator \((\Box+m^2)\) is dictated by the free dynamics and is shared by every Green's function. The delta-function source is manufactured entirely by the equal-time canonical commutator \([\dot\phi,\phi]=-i\delta^{(3)}\) hitting the discontinuity of the time-ordering symbol — this is the one place where quantization, not classical field theory, enters. And the choice of which Green's function is made once and for all by the \(+i\epsilon\), which is nothing but the analytic encoding of "later operators to the left." Three independent ingredients — dynamics, canonical structure, boundary condition — meet in a single object.
The contour prescription is where the vacuum's particle content is written. Closing the \(p^0\) integral below for \(x^0>y^0\) picks the pole at \(+E_{\vec p}\): a positive-energy quantum moving forward in time. Closing above for \(x^0<y^0\) picks \(-E_{\vec p}\): interpreted as a positive-energy antiparticle moving forward, or equivalently a negative-energy solution moving backward (Feynman–Stückelberg). A single analytic function thus describes particle and antiparticle propagation as two faces of one amplitude — the reason \(D_F\) and not the retarded propagator is the natural object for a relativistic quantum theory, where pair creation forbids a strictly forward-in-time single-particle description.
There is a deeper, Euclidean face. Rotating \(p^0\to ip^0_E\) (Wick rotation) turns \(p^2-m^2+i\epsilon\) into \(-(p_E^2+m^2)\), a strictly negative-definite denominator with no poles on the real axis — the \(i\epsilon\) is exactly what makes this rotation legal by keeping the poles off the rotating contour. The Feynman propagator is the analytic continuation of the Euclidean two-point function \(1/(p_E^2+m^2)\), the covariance of a Gaussian measure. This is why the path integral with the \(e^{-S_E}\) weight computes time-ordered correlators: the \(T\)-ordering and the \(+i\epsilon\) are the Lorentzian shadow of Euclidean reflection positivity. The same \(i\epsilon\) that orders operators is the one that guarantees convergence of the functional integral.
Common misconceptions. The propagator is not "the wavefunction of the particle" and it is not a probability. It is a two-point correlation function / transition amplitude, complex-valued, with an imaginary part that (via the optical theorem) measures the rate of real particle production. Nor does the internal line "put a real particle on shell": the four-momentum flowing through \(\tilde D_F(p)\) is integrated over all of \(p^0\), off shell everywhere except at the poles. Finally, \(D_F\) is symmetric, \(D_F(x-y)=D_F(y-x)\), even though the definition uses time ordering — the two \(\theta\)-terms exchange under \(x\leftrightarrow y\).
Worked examples
Reading. The Compton wavelength of the exchanged quantum sets the reach of the force. A 140 MeV pion gives a nuclear force of range \(\sim\!1.4\) fm — precisely the scale of the nucleon–nucleon interaction Yukawa predicted from exactly this propagator. A massless exchange (\(m\to0\)) gives infinite range: the Coulomb \(1/r\).
Reading. The propagator has poles only on the mass shell \(p^0=\pm E_{\vec p}\); the \(+i\epsilon\) nudges the \(+E_{\vec p}\) pole into the lower half-plane and the \(-E_{\vec p}\) pole into the upper half-plane — the analytic signature of time ordering. Away from the poles (here at \(p^0=200\) MeV) the internal line is off shell and its amplitude is finite and small, the hallmark of a virtual particle.
Problems
- Green's-function sign. Verify directly in momentum space that \(\tilde D_F(p)=i/(p^2-m^2+i\epsilon)\) satisfies \((\Box_x+m^2)D_F=-i\delta^{(4)}(x-y)\), and state what \(\tilde D_F\) would be if the source were \(+i\delta^{(4)}\) instead.
Solution
Acting with \((\Box_x+m^2)\) on \(D_F=\int\frac{d^4p}{(2\pi)^4}\tilde D_F(p)e^{-ip\cdot(x-y)}\) brings down \((-p^2+m^2)\). Thus \((\Box+m^2)D_F=\int\frac{d^4p}{(2\pi)^4}(m^2-p^2)\frac{i}{p^2-m^2+i\epsilon}e^{-ip\cdot(x-y)}\). As \(\epsilon\to0\), \((m^2-p^2)/(p^2-m^2)=-1\), so the integrand \(\to -i\,e^{-ip\cdot(x-y)}\), giving \(-i\int\frac{d^4p}{(2\pi)^4}e^{-ip\cdot(x-y)}=-i\,\delta^{(4)}(x-y)\). ✓ For a \(+i\delta^{(4)}\) source the residue flips: \(\tilde D_F=-i/(p^2-m^2+i\epsilon)\). - Yukawa transform. Show \(\displaystyle\int\!\frac{d^3p}{(2\pi)^3}\frac{e^{i\vec p\cdot\vec r}}{\vec p^{\,2}+m^2}=\frac{e^{-mr}}{4\pi r}\), and evaluate the ratio of the potential at \(r=0.5\) fm to that at \(r=1.5\) fm for \(m=140\) MeV.
Solution
Do the angular integral: \(\int d\Omega\,e^{i\vec p\cdot\vec r}=4\pi\,\frac{\sin(pr)}{pr}\). Then \(I=\frac{1}{(2\pi)^3}\int_0^\infty dp\,p^2\frac{4\pi}{pr}\frac{\sin pr}{p^2+m^2}=\frac{1}{2\pi^2 r}\int_0^\infty\frac{p\sin(pr)}{p^2+m^2}dp\). The remaining integral is \(\frac{\pi}{2}e^{-mr}\) (standard contour result), giving \(I=\frac{e^{-mr}}{4\pi r}\). ✓ With \(1/m=1.41\) fm: \(\frac{V(0.5)}{V(1.5)}=\frac{e^{-0.5/1.41}/0.5}{e^{-1.5/1.41}/1.5}=3\,e^{(1.5-0.5)/1.41}=3\,e^{0.709}\approx 3\times2.03\approx 6.1\). - Contour and time ordering. Perform the \(p^0\) integral \(\int\frac{dp^0}{2\pi}\frac{i\,e^{-ip^0 t}}{(p^0)^2-E^2+i\epsilon}\) by residues for \(t>0\) and \(t<0\), and identify the two on-shell frequencies with the terms of \(T\phi\phi\).
Solution
Poles at \(p^0=\pm(E-i\epsilon')\). For \(t>0\), \(e^{-ip^0t}\) decays as \(\mathrm{Im}\,p^0\to-\infty\), close below, enclosing \(p^0=+E-i\epsilon'\) clockwise: residue gives \(\frac{i}{2\pi}\cdot(-2\pi i)\frac{e^{-iEt}}{2E}=\frac{e^{-iEt}}{2E}\). For \(t<0\), close above, enclosing \(p^0=-E+i\epsilon'\) counterclockwise: \(\frac{e^{+iEt}}{2E}\). Combined: \(\frac{1}{2E}[\theta(t)e^{-iEt}+\theta(-t)e^{+iEt}]\). The \(\theta(t)e^{-iEt}\) term is \(\langle\phi(x)\phi(y)\rangle\) (positive frequency, forward); the \(\theta(-t)e^{+iEt}\) term is \(\langle\phi(y)\phi(x)\rangle\) — exactly the time-ordered product. - Massless propagator. Take \(m\to0\) and use \(\int\frac{d^4p}{(2\pi)^4}\frac{-i}{p^2+i\epsilon}e^{-ip\cdot x}=\frac{1}{4\pi^2}\frac{1}{x^2-i\epsilon}\) (up to sign) to identify the light-cone singularity structure. What is the mass dimension of this \(D_F\), and does it match \([\phi]^2\)?
Solution
\(D_F(x)=\frac{-1}{4\pi^2}\frac{1}{x^2-i\epsilon}\) with \(x^2=t^2-\vec x^2\). It is singular on the light cone \(x^2=0\); the \(-i\epsilon\) tells how to circle that singularity (principal value plus a \(\delta(x^2)\) piece supported on the cone, i.e. real massless propagation). Dimension: \([1/x^2]=+2=[\phi]^2\) for a scalar in 4D. ✓ The massless field mediates a long-range \(1/r\) (Coulomb) static potential, the \(m\to0\) limit of Yukawa. - Symmetry of the propagator. Prove \(D_F(x-y)=D_F(y-x)\) for the free scalar, and explain why this is consistent with the manifestly ordering-dependent definition via \(T\).
Solution
From the definition, \(D_F(y-x)=\theta(y^0-x^0)\langle\phi(y)\phi(x)\rangle+\theta(x^0-y^0)\langle\phi(x)\phi(y)\rangle\), which is the same two terms as \(D_F(x-y)\) with the roles of the \(\theta\)'s and correlators swapped in tandem — i.e. identical. Equivalently, in momentum space \(\tilde D_F(p)=i/(p^2-m^2+i\epsilon)\) is even in \(p\), so its Fourier transform is even in \(x-y\). The \(T\)-symbol is symmetric under exchanging both the operators and their time labels together, so no asymmetry survives. Physically: exchanging the endpoints swaps "emit then absorb" for "absorb then emit," and for the vacuum two-point function these give the same amplitude.