Constant Acceleration and the Uniformly Accelerated Observer
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You should be comfortable with the Lorentz transformation, the definition of the Lorentz factor \(\gamma\), and the basic kinematics of special relativity. Familiarity with hyperbolic functions is helpful but not strictly required, as we will introduce them as needed.
Why this matters
Uniform acceleration is the relativistic analogue of constant force, and it reveals the geometric structure of spacetime more clearly than any other motion.
In Newtonian mechanics, constant acceleration leads to simple parabolic trajectories. In special relativity, however, the relationship between force, acceleration, and velocity is non-linear due to the \(\gamma\) factor. Understanding how an object moves under constant proper acceleration allows us to define the "uniformly accelerated observer," a frame that is not inertial but has a well-defined horizon. This concept is crucial for understanding the Unruh effect and the geometry of Rindler coordinates, bridging the gap between special relativity and general relativity.
The Idea in Plain Language
Imagine you are in a rocket ship. In Newtonian physics, if you push the engine with a constant force, your speed increases linearly with time. You can keep accelerating forever, eventually exceeding the speed of light if you wait long enough. Special relativity forbids this. As your speed approaches the speed of light \(c\), your relativistic mass (or rather, your inertia) increases, meaning the same force produces less and less change in velocity.
However, there is a subtle distinction between "coordinate acceleration" (how fast your velocity changes as measured by a stationary observer) and "proper acceleration" (the acceleration you feel in your own frame, like the g-force pressing you into your seat). A "uniformly accelerated observer" is one who maintains a constant proper acceleration. This is the relativistic equivalent of standing on Earth's surface, where you feel a constant acceleration of \(9.8\ \mathrm{m/s^2}\) despite not moving relative to the ground. This state of motion is not just a limit case; it is a fundamental symmetry of Minkowski spacetime, described elegantly using hyperbolic geometry rather than circular trigonometry.
Rapidity: The Angle of Motion
To handle the non-linear addition of velocities, we introduce a new parameter called rapidity, denoted by \(\varphi\). Instead of adding velocities directly, which leads to the complex relativistic velocity addition formula, we add rapidities. This works because a Lorentz boost is mathematically equivalent to a hyperbolic rotation in the \((ct, x)\) plane.
The rapidity \(\varphi\) is defined such that the velocity \(\beta = v/c\) is given by \(\tanh \varphi\). The Lorentz factor \(\gamma\) is then \(\cosh \varphi\). This substitution transforms the Lorentz transformation matrix into a form that looks like a rotation matrix, but with hyperbolic functions:
The key advantage is that two successive boosts with rapidities \(\varphi_1\) and \(\varphi_2\) simply add: \(\varphi_{\text{total}} = \varphi_1 + \varphi_2\). This linearity makes the mathematics of constant acceleration tractable, as the rapidity changes linearly with proper time.
Kinematics of Constant Proper Acceleration
Let us consider a particle starting from rest at \(t=0, x=0\) and undergoing constant proper acceleration \(\alpha\). The proper acceleration is the acceleration measured in the instantaneous rest frame of the particle. From the relativistic force law, we know that for motion along one dimension, the relationship between proper acceleration \(\alpha\), coordinate acceleration \(a = dv/dt\), and velocity \(v\) is given by \(\alpha = \gamma^3 a\).
Since \(\gamma = \cosh \varphi\) and \(v = c \tanh \varphi\), we can express the dynamics in terms of rapidity. The proper time \(\tau\) is related to the coordinate time \(t\) by \(dt = \gamma d\tau = \cosh \varphi \, d\tau\). The change in rapidity is \(d\varphi = \frac{\alpha}{c} d\tau\). Integrating this from rest (\(\varphi=0\)) gives \(\varphi(\tau) = \frac{\alpha \tau}{c}\).
Using the hyperbolic identities, we can now write the position and time as functions of proper time \(\tau\):
Notice that as \(\tau \to \infty\), \(t \to \infty\) and \(x \to \infty\), but the velocity \(v = c \tanh(\alpha \tau / c)\) asymptotically approaches \(c\). The particle never reaches the speed of light, but it continues to accelerate in its own frame.
The Rindler Horizon
If we eliminate the proper time \(\tau\) from the equations above, we find a direct relationship between \(x\) and \(t\). Squaring the expressions and using \(\cosh^2 \theta - \sinh^2 \theta = 1\), we obtain:
This is the equation of a hyperbola in Minkowski spacetime. The asymptotes of this hyperbola are the lines \(x + c^2/\alpha = \pm ct\). These lines represent a boundary beyond which the accelerated observer can never send a signal. This boundary is known as the Rindler horizon. It is a direct consequence of the finite speed of light and the fact that the observer is constantly moving away from the origin faster than light signals can catch up to them from behind.
This horizon is not a physical barrier, but a causal limit. It demonstrates that even in flat spacetime, an accelerated observer has a restricted view of the universe, a concept that becomes central in quantum field theory in curved spacetime.
The derivations
Relativistic Force and Four-Acceleration
We define the four-force as the proper-time derivative of four-momentum, Fμ = dPμ/dτ, show that for a particle of constant rest mass it equals mass times four-acceleration, Fμ = mAμ, and reduce it to the three-force law f = mγa + mγ3(u·a)u/c2, whose parallel and perpendicular projections give f∥ = γ3ma∥ and f⊥ = γma⊥.
Rapidity and the Additivity of Boosts
A Lorentz boost along a fixed axis with speed \(v=\beta c\) is a hyperbolic rotation in the \((ct,x)\) plane through a hyperbolic angle \(\varphi\), the rapidity, defined by \(\tanh\varphi=\beta\) (equivalently \(\gamma=\cosh\varphi\), \(\gamma\beta=\sinh\varphi\)). Two collinear boosts of rapidities \(\varphi_1\) and \(\varphi_2\) compose into a single boost of rapidity \(\varphi=\varphi_1+\varphi_2\); taking \(\tanh\) of both sides reproduces the relativistic velocity-addition law \(\beta=(\beta_1+\beta_2)/(1+\beta_1\beta_2)\).
A common misconception is that "constant acceleration" in relativity means constant coordinate acceleration \(a = dv/dt\). It does not. Constant proper acceleration \(\alpha\) results in a coordinate acceleration that decreases with time as \(a(t) = \alpha / \gamma^3(t)\). If you assume \(a\) is constant, you will derive the Newtonian result \(x = \frac{1}{2}at^2\), which violates the light-speed limit. Always distinguish between the acceleration felt by the observer (proper) and the acceleration measured by an inertial frame (coordinate). C
Worked example
Problem. A spaceship of negligible mass undergoes constant proper acceleration \(\alpha = 1.0\ \mathrm{m/s^2}\) starting from rest at \(t=0\). Calculate the coordinate time \(t\) and position \(x\) when the spaceship reaches a speed of \(v = 0.9c\). Use \(c = 3.0 \times 10^8\ \mathrm{m/s}\).
- Determine the rapidity \(\varphi\) corresponding to \(v = 0.9c\). Since \(\beta = 0.9\), \(\varphi = \operatorname{artanh}(0.9)\). \[ \varphi = \frac{1}{2} \ln\left(\frac{1+0.9}{1-0.9}\right) = \frac{1}{2} \ln(19) \approx 1.472 \]
- Calculate the Lorentz factor \(\gamma = \cosh \varphi\). \[ \gamma = \frac{1}{\sqrt{1 - 0.9^2}} = \frac{1}{\sqrt{0.19}} \approx 2.294 \]
- Find the proper time \(\tau\) using \(\varphi = \frac{\alpha \tau}{c}\). \[ \tau = \frac{c \varphi}{\alpha} = \frac{(3.0 \times 10^8)(1.472)}{1.0} \approx 4.42 \times 10^8\ \mathrm{s} \]
- Calculate the coordinate time \(t = \frac{c}{\alpha} \sinh \varphi\). Note that \(\sinh \varphi = \gamma \beta = 2.294 \times 0.9 \approx 2.065\). \[ t = \frac{3.0 \times 10^8}{1.0} \times 2.065 \approx 6.20 \times 10^8\ \mathrm{s} \]
- Calculate the position \(x = \frac{c^2}{\alpha} (\cosh \varphi - 1)\). \[ x = \frac{(3.0 \times 10^8)^2}{1.0} (2.294 - 1) = 9.0 \times 10^{16} \times 1.294 \approx 1.16 \times 10^{17}\ \mathrm{m} \]
Units check. Time is in seconds. Position: \(\frac{\mathrm{m^2/s^2}}{\mathrm{m/s^2}} = \mathrm{m}\). The result is consistent with SI units.
Three quick tests
- What is the relationship between rapidity \(\varphi\) and velocity \(\beta\)?
Answer
\(\beta = \tanh \varphi\). - Does a uniformly accelerated observer have a horizon?
Answer
Yes, the Rindler horizon, which is a causal boundary in flat spacetime. - If proper acceleration is constant, is coordinate acceleration constant?
Answer
No, coordinate acceleration decreases as velocity increases, following \(a = \alpha / \gamma^3\).
Problem set for PU-105 →
Each derivation in this unit ends with five graded problems with full solutions.
Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.
Derivations cited: D-103 · D-096 · Threads: force, energy, light