Rapidity: Boosts as Hyperbolic Rotations
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You should be comfortable with the Lorentz transformation matrix and the relativistic velocity addition formula. Familiarity with basic hyperbolic functions (\(\sinh\), \(\cosh\), \(\tanh\)) is required.
Why this matters
Rapidity provides a linear parameter for relativistic boosts, simplifying the composition of velocities.
In classical mechanics, adding velocities is straightforward: if you run at speed \(u\) on a train moving at speed \(v\), your total speed is \(u+v\). In special relativity, this simple sum fails because the speed of light must remain invariant for all observers. The relativistic velocity addition formula involves a complex denominator, making the composition of multiple boosts algebraically cumbersome. By introducing rapidity, we transform the non-linear addition of velocities into a simple linear addition of angles, revealing the underlying geometric structure of spacetime as a hyperbolic plane rather than a Euclidean one.
The Geometric Intuition
Imagine a standard rotation in a 2D plane. If you rotate a vector by an angle \(\theta_1\) and then by \(\theta_2\), the total rotation is simply \(\theta_1 + \theta_2\). This additivity is a fundamental property of Euclidean rotations. However, Lorentz boosts do not preserve the Euclidean distance \(x^2 + y^2\); instead, they preserve the Minkowski interval \(s^2 = c^2t^2 - x^2\). This minus sign changes the geometry from circular to hyperbolic.
Just as circular rotations are described by sine and cosine, hyperbolic rotations (boosts) are described by hyperbolic sine and hyperbolic cosine. The "angle" in this hyperbolic rotation is not the physical speed \(v\), but a new quantity called rapidity, denoted by \(\varphi\). The key insight is that while velocities do not add linearly, rapidities do. If you boost into a frame moving at rapidity \(\varphi_1\), and then boost again by \(\varphi_2\), the total boost is simply \(\varphi_1 + \varphi_2\). This linear additivity is the primary mathematical advantage of using rapidity over velocity.
Defining Rapidity
We define the rapidity \(\varphi\) such that it parameterizes the Lorentz boost matrix. The standard Lorentz transformation for a boost along the \(x\)-axis is given by:
where \(\beta = v/c\) and \(\gamma = 1/\sqrt{1-\beta^2}\). We seek a parameter \(\varphi\) such that the matrix elements can be written using hyperbolic functions. We identify the following relationships:
Dividing the second equation by the first, we obtain the fundamental definition of rapidity:
Conversely, the rapidity is the inverse hyperbolic tangent of the normalized velocity:
Note that as \(v \to c\), \(\beta \to 1\), and \(\varphi \to \infty\). This reflects the fact that an infinite amount of rapidity (and thus infinite energy) is required to reach the speed of light.
Additivity of Boosts
The power of rapidity becomes evident when composing two boosts. Consider two collinear boosts with rapidities \(\varphi_1\) and \(\varphi_2\). The corresponding Lorentz matrices are \(B(\varphi_1)\) and \(B(\varphi_2)\). The composition of these transformations is the product of their matrices:
Using the hyperbolic addition formulas \(\cosh(A+B) = \cosh A \cosh B + \sinh A \sinh B\) and \(\sinh(A+B) = \sinh A \cosh B + \cosh A \sinh B\), the product simplifies exactly to a single boost matrix with rapidity \(\varphi_1 + \varphi_2\):
This result is significantly cleaner than the relativistic velocity addition formula. If we convert back to velocities, we recover the standard law. Since \(\beta = \tanh\varphi\), the total velocity \(\beta_{\text{total}}\) is:
Thus, rapidity linearizes the group structure of Lorentz boosts, making it the natural coordinate for describing relativistic motion.
Rapidity in Particle Physics
In high-energy physics, rapidity is often more useful than velocity or momentum. Consider a particle with energy \(E\) and momentum \(p\). We can define the particle's rapidity \(\eta\) (often distinct from the frame rapidity \(\varphi\), though related) via:
For a massless particle, \(E = p\), and this definition requires careful limiting treatment, but for massive particles, it provides a measure of the "boost" required to bring the particle to rest. A crucial property is that the difference in rapidity between two particles, \(\Delta \eta = \eta_1 - \eta_2\), is invariant under longitudinal boosts. This makes rapidity the ideal variable for analyzing collisions in accelerators, where the center-of-mass frame may be difficult to determine directly, but the relative rapidity of the products is physically meaningful.
The derivation
Rapidity and the Additivity of Boosts
A Lorentz boost along a fixed axis with speed \(v=\beta c\) is a hyperbolic rotation in the \((ct,x)\) plane through a hyperbolic angle \(\varphi\), the rapidity, defined by \(\tanh\varphi=\beta\) (equivalently \(\gamma=\cosh\varphi\), \(\gamma\beta=\sinh\varphi\)). Two collinear boosts of rapidities \(\varphi_1\) and \(\varphi_2\) compose into a single boost of rapidity \(\varphi=\varphi_1+\varphi_2\); taking \(\tanh\) of both sides reproduces the relativistic velocity-addition law \(\beta=(\beta_1+\beta_2)/(1+\beta_1\beta_2)\).
Rapidity is only additive for collinear boosts. If you boost in the \(x\)-direction and then in the \(y\)-direction, the resulting transformation is not a pure boost but a boost combined with a spatial rotation (Wigner rotation). Therefore, the simple linear addition \(\varphi_{\text{total}} = \varphi_x + \varphi_y\) is invalid for non-collinear axes. C
Worked example
Problem. A spaceship moves at \(0.6c\) relative to Earth. A probe is launched from the spaceship at \(0.8c\) relative to the spaceship, in the same direction. Calculate the velocity of the probe relative to Earth using rapidity.
- Calculate the rapidity of the spaceship relative to Earth: \(\varphi_1 = \operatorname{artanh}(0.6)\). Using \(\operatorname{artanh}(x) = \frac{1}{2}\ln\frac{1+x}{1-x}\), \(\varphi_1 = \frac{1}{2}\ln\frac{1.6}{0.4} = \frac{1}{2}\ln(4) \approx 0.6931\).
- Calculate the rapidity of the probe relative to the spaceship: \(\varphi_2 = \operatorname{artanh}(0.8)\). \(\varphi_2 = \frac{1}{2}\ln\frac{1.8}{0.2} = \frac{1}{2}\ln(9) \approx 1.0986\).
- Add the rapidities: \(\varphi_{\text{total}} = \varphi_1 + \varphi_2 = 0.6931 + 1.0986 = 1.7917\).
- Convert back to velocity: \(\beta_{\text{total}} = \tanh(1.7917)\). \(\tanh(1.7917) = \frac{e^{1.7917} - e^{-1.7917}}{e^{1.7917} + e^{-1.7917}} \approx \frac{6.0 - 0.1667}{6.0 + 0.1667} \approx \frac{5.8333}{6.1667} \approx 0.946\).
Units check. The result is a fraction of the speed of light \(c\), which is dimensionless. The physical velocity is \(0.946 \times 3.00 \times 10^8\ \mathrm{m/s}\), consistent with SI units for velocity.
Three quick tests
- What is the rapidity of a particle moving at \(v = c\)?
Answer
Infinite. As \(\beta \to 1\), \(\operatorname{artanh}(\beta) \to \infty\). - If two boosts have rapidities \(\varphi_1 = 1\) and \(\varphi_2 = 2\), what is the rapidity of the composite boost?
Answer
3. Rapidity is additive for collinear boosts: \(\varphi_{\text{total}} = 1 + 2 = 3\). - Does the rapidity of a particle change if you observe it from a different inertial frame moving along the same axis?
Answer
Yes. The rapidity relative to the new frame is the difference between the particle's rapidity and the frame's rapidity. It is not invariant, but the difference between two particles' rapidities is invariant under longitudinal boosts.
Problem set for PU-105 →
Each derivation in this unit ends with five graded problems with full solutions.
Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.