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PU-103 / L23 · lecture

Plane Waves in Two and Three Dimensions

~6 min read · Tier toggle changes depth (T1 plain · T2 standard · T3 rigour)

BEFORE YOU START

You should be comfortable with the one-dimensional wave equation, d'Alembert's solution, and the definitions of phase and group velocity from the previous lecture.

Why this matters

Real-world waves propagate in three dimensions, not just along a single string.

Extending the wave equation to two and three dimensions allows us to describe sound in air, light in vacuum, and vibrations in membranes. The mathematical structure remains remarkably similar to the one-dimensional case, but the physical interpretation of "direction" and "shape" becomes richer. This lecture bridges the gap between the idealised 1D string and the complex field phenomena encountered in electromagnetism and acoustics.

From Strings to Fields

Imagine a stretched drumhead. When you strike it, the disturbance does not travel in one direction only; it spreads out in all directions across the surface. In one dimension, a wave is a simple function of position \(x\) and time \(t\). In two dimensions, the displacement \(u\) depends on \(x\), \(y\), and \(t\). In three dimensions, it depends on \(x\), \(y\), \(z\), and \(t\). The core idea remains the same: the acceleration of a point in the medium is proportional to the curvature of the displacement field around that point. This curvature is measured by the Laplacian operator, which generalises the second derivative with respect to position. A plane wave in this context is a wave whose crests and troughs are flat planes, moving perpendicular to those planes. It is the simplest possible wave in higher dimensions, analogous to a pure sine wave in one dimension.

The Multi-Dimensional Wave Equation

For a homogeneous, isotropic medium, the wave equation in \(n\) spatial dimensions is given by:

\[ \frac{\partial^2 u}{\partial t^2} = c^2 \nabla^2 u \]

where \(c\) is the wave speed and \(\nabla^2\) is the Laplacian operator. In three Cartesian coordinates, the Laplacian is defined as:

\[ \nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2} \]

A plane wave travelling in the direction of a unit vector \(\hat{\mathbf{n}}\) can be written as a function of the projection of the position vector \(\mathbf{r}\) onto \(\hat{\mathbf{n}}\). Let \(\mathbf{k} = k \hat{\mathbf{n}}\) be the wave vector, where \(k\) is the wavenumber. The phase is \(\phi = \mathbf{k} \cdot \mathbf{r} - \omega t\). A general plane wave solution is:

\[ u(\mathbf{r}, t) = A \cos(\mathbf{k} \cdot \mathbf{r} - \omega t + \delta) \]

Substituting this into the wave equation shows that it is a valid solution provided the dispersion relation \(\omega = c k\) holds. This confirms that in a non-dispersive medium, the speed \(c\) is independent of frequency and direction.

Wave Vectors and Direction

The wave vector \(\mathbf{k}\) encodes both the spatial frequency and the direction of propagation. Its magnitude \(k = 2\pi/\lambda\) determines the wavelength, while its direction \(\hat{\mathbf{n}}\) indicates the normal to the wavefronts. In two dimensions, if a wave travels at an angle \(\theta\) to the \(x\)-axis, we can decompose \(\mathbf{k}\) into components \(k_x = k \cos \theta\) and \(k_y = k \sin \theta\). The phase becomes \(\phi = k_x x + k_y y - \omega t\). This decomposition is crucial for understanding interference and diffraction, where multiple plane waves with different \(\mathbf{k}\) vectors superpose to form complex patterns. The surfaces of constant phase are planes defined by \(\mathbf{k} \cdot \mathbf{r} = \text{constant}\), which are perpendicular to \(\mathbf{k}\).

Dispersion in Higher Dimensions

While the 1D analysis of dispersion is intuitive, it generalises directly to \(N\) dimensions. The dispersion relation \(\omega = \omega(\mathbf{k})\) may depend on the magnitude \(k = |\mathbf{k}|\) and, in anisotropic media, on the direction of \(\mathbf{k}\). For an isotropic medium, \(\omega\) depends only on \(k\). The phase velocity is still \(v_p = \omega/k\). However, the group velocity, which represents the energy transport direction, is given by the gradient of \(\omega\) with respect to \(\mathbf{k}\):

\[ \mathbf{v}_g = \nabla_{\mathbf{k}} \omega \]

In an isotropic medium, this vector points in the same direction as \(\mathbf{k}\), and its magnitude is \(v_g = d\omega/dk\). If the medium is dispersive, \(v_g \neq v_p\), and the wave packet spreads out as it propagates. This spreading is a fundamental feature of wave motion in higher dimensions and is responsible for phenomena such as chromatic dispersion in optics.

The derivations

◆ DERIVATION EMBED · D-065 · not re-derived here

d'Alembert's General Solution

On the whole line \(x\in\mathbb{R}\), every twice-differentiable solution of the one-dimensional wave equation \(\partial_{tt}u=c^{2}\,\partial_{xx}u\) can be written as \(u(x,t)=f(x-ct)+g(x+ct)\), a rigidly translating right-moving profile \(f\) superposed on a rigidly translating left-moving profile \(g\); conversely any such \(C^2\) sum solves the equation. When the initial displacement \(u(x,0)=\phi(x)\) and velocity \(\partial_t u(x,0)=\psi(x)\) are prescribed, the solution is unique and given explicitly by \(u(x,t)=\tfrac12\big[\phi(x-ct)+\phi(x+ct)\big]+\tfrac{1}{2c}\int_{x-ct}^{x+ct}\psi(s)\,ds\).

\[ u(x,t)=f(x-ct)+g(x+ct)=\frac{\phi(x-ct)+\phi(x+ct)}{2}+\frac{1}{2c}\int_{x-ct}^{x+ct}\psi(s)\,ds \]
Open full derivation →
◆ DERIVATION EMBED · D-071 · not re-derived here

Dispersion, Phase Velocity and Group Velocity

For a linear, homogeneous medium whose plane-wave solutions obey a dispersion relation \(\omega=\omega(k)\), a single sinusoidal component \(\psi=A\cos(kx-\omega t)\) advances its surfaces of constant phase at the phase velocity \(v_p=\omega/k\), whereas the envelope of a narrow-band superposition of such components advances at the group velocity \(v_g=\dfrac{d\omega}{dk}\). The two coincide only when \(\omega\) is strictly proportional to \(k\); otherwise the medium is dispersive and it is \(v_g\), not \(v_p\), that carries the modulation, energy, and signal to leading order.

\[ v_p=\frac{\omega}{k},\qquad v_g=\frac{d\omega}{dk}=v_p+k\,\frac{dv_p}{dk} \]
Open full derivation →
Tier 3 ยท watch out

A common misconception is that the wave vector \(\mathbf{k}\) always points in the direction of energy flow. In anisotropic media, such as crystals, the phase velocity direction (normal to wavefronts) and the group velocity direction (energy flow) can differ. This leads to phenomena like birefringence, where a single incident beam splits into two orthogonal polarisation modes travelling at different speeds and directions. C

Worked example

Problem. Waves in an isotropic 2D medium obey \(\omega = c k + \alpha k^2\) with \(k = |\mathbf k|\), \(c = 300\ \mathrm{m/s}\) and \(\alpha = 0.050\ \mathrm{m^2/s}\). For \(\mathbf k = (4\pi, 4\pi)\ \mathrm{rad/m}\), find the phase velocity and the group velocity vector.

  1. Magnitude: \(k = \sqrt{(4\pi)^2 + (4\pi)^2} = 4\sqrt{2}\,\pi \approx 17.77\ \mathrm{rad/m}\).
  2. Angular frequency: \(\omega = (300)(17.77) + (0.050)(17.77)^2 \approx 5331.6 + 15.8 \approx 5.35 \times 10^{3}\ \mathrm{rad/s}\).
  3. Phase velocity: \(v_p = \omega/k = c + \alpha k = 300 + (0.050)(17.77) \approx 300.89\ \mathrm{m/s}\).
  4. Group velocity: because \(\omega\) depends only on \(k = |\mathbf k|\), \(\mathbf v_g = \nabla_{\mathbf k}\,\omega = \dfrac{d\omega}{dk}\,\hat{\mathbf k}\), with \(d\omega/dk = c + 2\alpha k \approx 300 + 1.78 = 301.78\ \mathrm{m/s}\).
  5. Components: \(\hat{\mathbf k} = (1, 1)/\sqrt 2\), so \(\mathbf v_g \approx (213.4,\ 213.4)\ \mathrm{m/s}\), parallel to \(\mathbf k\) as expected in an isotropic medium.
\[ v_p \approx 300.9\ \mathrm{m/s}, \qquad \mathbf v_g \approx (213.4,\ 213.4)\ \mathrm{m/s},\ |\mathbf v_g| \approx 301.8\ \mathrm{m/s} \]

Units check. \(\alpha k\) is \((\mathrm{m^2/s})(\mathrm{m^{-1}}) = \mathrm{m/s}\), the same as \(c\); \(\alpha k^2\) is \(\mathrm{s^{-1}}\), the same as \(ck\).

CHECK YOURSELF

Three quick tests

  1. What is the direction of propagation for a plane wave with wave vector \(\mathbf{k} = (0, 5, 0)\ \mathrm{rad/m}\)?
    AnswerAlong the positive \(y\)-axis.
  2. If \(\omega = c k\), what is the relationship between phase and group velocity?
    AnswerThey are equal: \(v_p = v_g = c\).
  3. In an anisotropic medium, does \(\mathbf{k}\) always point in the direction of energy flow?
    AnswerNo, \(\mathbf{v}_g\) (energy flow) can differ in direction from \(\mathbf{k}\) (phase normal).
PROBLEMS

Problem set for PU-103 →

Each derivation in this unit ends with five graded problems with full solutions.

NOTES

Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.

Derivations cited: D-065 · D-071 · Threads: force, energy, waves