Transition state theory
Statement
Rate from the activated complex at the barrier top.
Why it matters
collision-theory gives a first, mechanical picture of a reaction rate as a collision frequency multiplied by an energetic and orientational requirement, but it treats molecules as crude hard spheres and can only patch up its systematic failure to predict the pre-exponential factor for complex reactions with an ad hoc "steric factor." Transition state theory (TST) replaces that picture with a proper thermodynamic/statistical treatment of the activated complex sitting at the top of the reaction's energy barrier, giving arrhenius-equation's empirical parameters, \(E_a\) and \(A\), a genuine theoretical foundation.
Because TST expresses the rate constant through thermodynamic-style activation parameters (\(\Delta H^{\ddagger}\), \(\Delta S^{\ddagger}\)) rather than through a purely kinetic collision picture, it also connects naturally to steady-state-approximation: TST supplies the rate constant for each individual elementary step in a proposed mechanism, while the SSA is the separate tool for combining those elementary rate constants into an overall observed rate law.
Hypotheses
Proof
Result
Reading. The rate constant is expressed through the thermodynamic activation parameters of a hypothesised transition state rather than through a purely kinetic collision picture, giving both a barrier height (\(\Delta H^{\ddagger}\)) and an order/probability term (\(\Delta S^{\ddagger}\)) direct physical meaning.
Scope. Requires the quasi-equilibrium and no-recrossing assumptions (Hypotheses); neglects quantum tunnelling, most significant for light-atom transfer at low temperature.
Corollaries & converses
- A negative \(\Delta S^{\ddagger}\) corresponds to a highly ordered, restrictive transition state — typical of a bimolecular association reaction — exactly the situation collision-theory could only capture crudely with its empirical steric factor.
- Comparing Steps 4 and 5 shows \(E_a\approx\Delta H^{\ddagger}+RT\) for a reaction in solution, linking arrhenius-equation's empirical activation energy directly to a genuine thermodynamic quantity.
- steady-state-approximation and transition-state-theory address complementary aspects of the same kinetic problem: SSA extracts an observed rate law from a proposed multi-step mechanism, while TST supplies the theoretical rate constant for each individual elementary step feeding into that mechanism.
Fails without
- Drop the no-recrossing assumption: if a significant fraction of activated complexes revert back to reactants rather than proceeding on to products, Step 2's rate expression, built from the full quasi-equilibrium concentration of \(\text{X}^{\ddagger}\) alone, systematically overestimates the true rate; a transmission coefficient correcting for recrossing is needed to fix this in a more refined treatment.
- Ignore quantum tunnelling for a light-particle transfer reaction (Hypotheses' \(t3\)): the classical TST rate can substantially underestimate the true observed rate for hydrogen or proton transfer, especially at low temperature, since tunnelling opens an additional, purely quantum-mechanical pathway through, rather than over, the barrier that the classical treatment cannot capture at all.
Common errors
- Treating the activated complex as a real, isolable chemical species, rather than a formal, quasi-equilibrium construct at the potential-energy maximum.
- Confusing \(\Delta H^{\ddagger}\) with the reaction's overall thermodynamic \(\Delta H\) — the activation enthalpy concerns only the barrier from reactants to the transition state, independent of whether the overall reaction is exothermic or endothermic.
- Assuming a negative \(\Delta S^{\ddagger}\) indicates an error in the analysis, rather than recognising it as the expected, typical sign for essentially any bimolecular association reaction.
- Neglecting that classical TST, as developed here, entirely omits quantum tunnelling, which can noticeably raise the true rate above the TST prediction for light-particle transfer.
Discussion
Transition-state theory was developed largely by Henry Eyring, along with Meredith Gwynne Evans and Michael Polanyi, in the mid-1930s, which is why the rate expression derived here is commonly called the Eyring equation. It represented a substantial conceptual advance over collision theory, replacing a purely mechanical, hard-sphere collision picture with a genuinely thermodynamic and statistical treatment grounded in the quantum statistical mechanics then being developed.
Quantum mechanical tunnelling allows a reacting system some non-zero probability of passing through, rather than over, the activation barrier, an effect entirely outside classical TST's scope; it is most pronounced for the lightest nuclei (hydrogen and its isotopes) and becomes proportionally more important as temperature is lowered, since the classical over-the-barrier route becomes increasingly disfavoured while the tunnelling probability is comparatively insensitive to temperature.
Common misconception: that a large activation energy inherently reflects a large activation enthalpy alone, with entropy playing no role. Step 5's expansion of \(\Delta G^{\ddagger}\) shows the observed rate is jointly controlled by both an enthalpic barrier and an entropic term, and a slow reaction can have a comparatively modest \(\Delta H^{\ddagger}\) but a strongly unfavourable, very negative \(\Delta S^{\ddagger}\).
Worked examples
Reading. A single measured rate constant, together with temperature, converts directly through the Eyring equation into an activation Gibbs energy, without needing to separately measure \(\Delta H^{\ddagger}\) and \(\Delta S^{\ddagger}\) individually.
Scope. Separating \(\Delta G^{\ddagger}\) into \(\Delta H^{\ddagger}\) and \(\Delta S^{\ddagger}\) individually requires measuring \(k\) at several temperatures and analysing the resulting Eyring plot, analogous to how an Arrhenius plot separately extracts \(E_a\) and \(A\).
Problems
- A reaction has \(k=1.0\times10^{-2}\,\text{s}^{-1}\) at \(T=310\,\text{K}\). Compute \(K^{\ddagger}\) using \(k_BT/h\approx6.46\times10^{12}\,\text{s}^{-1}\) at this temperature.
Solution
\(K^{\ddagger}=k/(k_BT/h)=1.0\times10^{-2}/6.46\times10^{12}\approx1.55\times10^{-15}\). - Two bimolecular reactions have similar \(\Delta H^{\ddagger}\) but very different rates at the same temperature. Explain, in terms of \(\Delta S^{\ddagger}\), how this is possible.
Solution
By Step 5's Eyring expression, the rate constant depends on both \(\Delta H^{\ddagger}\) (through the exponential barrier term) and \(\Delta S^{\ddagger}\) (through the pre-exponential entropy term). If the two reactions have similar \(\Delta H^{\ddagger}\) but very different rates, the difference must arise predominantly from \(\Delta S^{\ddagger}\): a reaction requiring a much more restrictive, precisely ordered transition state (more negative \(\Delta S^{\ddagger}\)) will be markedly slower than one with a more loosely constrained transition state, even at an identical activation enthalpy. - Explain qualitatively why a sterically demanding bimolecular reaction (requiring precise mutual orientation of two large reactants) is expected to have a strongly negative \(\Delta S^{\ddagger}\), and relate this to how collision theory would instead describe the same effect.
Solution
Forming a highly specific, precisely oriented transition state from two independently tumbling reactant molecules represents a large loss of rotational and translational freedom, giving a strongly negative \(\Delta S^{\ddagger}\) (Corollaries). Collision theory, lacking any thermodynamic activation-entropy concept, can only capture this same steric demand indirectly, through an empirically fitted "steric factor" reducing the predicted rate below the simple collision-frequency estimate — TST's \(\Delta S^{\ddagger}\) gives this same physical effect a proper theoretical basis instead.