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CU-101 / L13 · lecture

The Schrödinger Equation for the Atom

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BEFORE YOU START

You should be comfortable with the concept of wave-particle duality and understand that the Uncertainty Principle forbids defining precise electron trajectories, necessitating a probabilistic description of atomic states.

Why this matters

The Schrödinger equation provides the mathematical foundation for the periodic table and chemical bonding.

While the Bohr model offered a useful first approximation, it failed to explain the shapes of orbitals or the behaviour of multi-electron atoms. The time-independent Schrödinger equation, when applied to the hydrogen atom, yields wavefunctions that describe the probability distribution of an electron in space. These solutions are not arbitrary; they are constrained by boundary conditions that lead directly to the quantum numbers governing atomic structure. Understanding this derivation is essential because it explains why electrons occupy specific energy levels and spatial regions, which in turn dictates the chemical properties of elements.

The Wave Nature of the Electron

Imagine an electron not as a tiny planet orbiting a nucleus, but as a standing wave wrapped around the nucleus. Just as a guitar string can only vibrate at specific frequencies that fit its length, an electron in an atom can only exist in states where its wavefunction forms a stable, non-decaying pattern. If the wave does not fit perfectly around the nucleus, it interferes destructively with itself and vanishes. This requirement for a "standing wave" is the physical origin of quantization. The Schrödinger equation is the mathematical tool that finds these allowed standing wave patterns. It tells us not where the electron is, but where it is likely to be found, and how much energy it possesses in that state.

The Time-Independent Schrödinger Equation

For a system where the potential energy does not change with time, such as an electron in a static Coulomb field of a nucleus, we use the time-independent Schrödinger equation. In compact operator form it reads:

\[ \hat{H}\psi = E\psi \]

Here, \(\hat{H}\) is the Hamiltonian operator, which represents the total energy of the system. For a hydrogen-like atom, the Hamiltonian consists of the kinetic energy operator and the potential energy operator due to the electrostatic attraction between the electron and the nucleus. The wavefunction \(\psi\) is the unknown we seek to solve for, and \(E\) is the allowed energy value. In three dimensions, the kinetic energy term involves the Laplacian operator \(\nabla^2\), which accounts for the curvature of the wave in space. The equation is a partial differential equation, meaning its solution depends on spatial coordinates \(x\), \(y\), and \(z\).

Separation of Variables in Spherical Coordinates

Because the potential energy in a hydrogen atom depends only on the distance \(r\) from the nucleus, the problem is spherically symmetric. It is therefore most efficient to solve the equation using spherical coordinates \((r, \theta, \phi)\) rather than Cartesian coordinates. We assume the total wavefunction \(\psi(r, \theta, \phi)\) can be written as a product of three separate functions, one for each coordinate: \(\psi = R(r) \Theta(\theta) \Phi(\phi)\). This technique, known as separation of variables, allows us to break one complex three-dimensional equation into three simpler one-dimensional equations. Each of these separated equations must be satisfied independently, and each introduces a constant of separation. These constants are not arbitrary; they are determined by the requirement that the wavefunction must be finite and single-valued everywhere in space.

Boundary Conditions and Quantum Numbers

The physical requirement that the probability of finding the electron must be finite and normalizable imposes strict constraints on the solutions. The radial equation \(R(r)\) yields the principal quantum number \(n\), which determines the energy level and the size of the orbital. The angular equations \(\Theta(\theta)\) and \(\Phi(\phi)\) yield the orbital angular momentum quantum number \(l\) and the magnetic quantum number \(m_l\). The integer \(l\) defines the shape of the orbital (s, p, d, etc.), while \(m_l\) defines its orientation in space. The boundary conditions force these values to be integers within specific ranges. For a given \(n\), \(l\) can take integer values from 0 to \(n-1\). For a given \(l\), \(m_l\) can take integer values from \(-l\) to \(+l\). These constraints arise naturally from the mathematics of the differential equations and are not imposed arbitrarily. The spin quantum number \(m_s\) is not derived from the Schrödinger equation for spatial coordinates but is an intrinsic property of the electron, taking values \(\pm\tfrac12\).

\[ n=1,2,3,\dots;\quad l=0,\dots,n-1;\quad m_l=-l,\dots,+l;\quad m_s=\pm\tfrac12 \]

The result

◆ RESULT · T-003 · full treatment on its own page

Quantum numbers and atomic orbitals

Solving the time-independent Schrödinger equation for an electron in a hydrogen-like atom, by separating variables in spherical coordinates, forces every stationary electron state to be labelled by three integers arising from the boundary conditions on the separated equation, plus a fourth from electron spin: the principal quantum number \(n=1,2,3,\dots\) (energy shell), the orbital angular momentum quantum number \(l=0,1,\dots,n-1\) (orbital shape), the magnetic quantum number \(m_l=-l,\dots,+l\) (orbital orientation), and the spin quantum number \(m_s=\pm\tfrac12\) (intrinsic electron spin). Each allowed \((n,l,m_l)\) triple defines one atomic orbital — a specific spatial probability-density pattern — and each orbital holds at most two electrons, one with each value of \(m_s\).

\[ n=1,2,3,\dots;\quad l=0,\dots,n-1;\quad m_l=-l,\dots,+l;\quad m_s=\pm\tfrac12 \]
Open the full result →
Tier 3 · watch out

A common misconception is that the Schrödinger equation for hydrogen directly predicts the spin of the electron. In reality, the non-relativistic Schrödinger equation only describes the spatial wavefunction and yields \(n\), \(l\), and \(m_l\). Electron spin is a relativistic quantum mechanical property that must be introduced separately, often via the Dirac equation or as an empirical addition to the quantum number scheme. Confusing the origin of \(m_s\) with the spatial quantum numbers leads to incorrect interpretations of fine structure and magnetic properties. C

Worked example

Problem. Determine the total number of distinct atomic orbitals available to an electron in the third principal energy shell (\(n=3\)) of a hydrogen-like atom, and calculate the maximum number of electrons that can occupy this shell.

  1. Identify the allowed values of the orbital angular momentum quantum number \(l\) for \(n=3\). According to the rule \(l=0, \dots, n-1\), the allowed values are \(l=0\), \(l=1\), and \(l=2\).
  2. For each value of \(l\), determine the number of allowed magnetic quantum numbers \(m_l\). The number of orbitals for a given \(l\) is \(2l+1\).
    • For \(l=0\) (s-subshell): \(m_l=0\). Number of orbitals = \(2(0)+1 = 1\).
    • For \(l=1\) (p-subshell): \(m_l=-1, 0, +1\). Number of orbitals = \(2(1)+1 = 3\).
    • For \(l=2\) (d-subshell): \(m_l=-2, -1, 0, +1, +2\). Number of orbitals = \(2(2)+1 = 5\).
  3. Sum the number of orbitals for all subshells in the \(n=3\) shell: \(1 + 3 + 5 = 9\) orbitals.
  4. Calculate the maximum number of electrons. Each orbital can hold two electrons (one with \(m_s=+\tfrac12\) and one with \(m_s=-\tfrac12\)). Therefore, the maximum number of electrons is \(9 \times 2 = 18\).
\[ \boxed{9\ \text{orbitals},\ 18\ \text{electrons}} \]

Units check. The quantities are dimensionless counts of quantum states, so no physical units are required, but the integer nature of the quantum numbers ensures the counts are exact.

CHECK YOURSELF

Three quick tests

  1. What is the physical significance of the wavefunction \(\psi\) in the Schrödinger equation?
    Answer\(\psi\) is a complex-valued function whose square modulus \(|\psi|^2\) gives the probability density of finding the electron at a specific point in space.
  2. Why must the quantum numbers \(n\), \(l\), and \(m_l\) be integers?
    AnswerThey arise from the boundary conditions required for the wavefunction to be finite, single-valued, and normalizable. Non-integer solutions lead to wavefunctions that diverge or are multi-valued, which are physically unacceptable.
  3. How many orbitals are in the \(n=2\) shell?
    AnswerFor \(n=2\), \(l\) can be 0 or 1. \(l=0\) has 1 orbital, \(l=1\) has 3 orbitals. Total = 4 orbitals.
UNIT

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NOTES

Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.

Results cited: T-003 · Threads: quantum, structure